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"F" exerted on the small piston at the end of the beam. Then fluid will flow through a valve 'a' toward large cylinders. Pull upwards the end of the beam, and the small piston will move upwards, valve 'a' will block the fluid reverse. Valve 'b' is open to let the fluid from the storage tank flow into a small cylinder. When you press the beam down again, the fluid will flow into the big cylinder again. Repeatly the cycle move up and down in several times to make fluid level more in the big piston to be able to lift a weight W higher. To let the weight W dropping down ,just open valve 'c', and fluid will allowed to flow into the storage tank. |
Example 9.4 Hydraulic Lift The big piston of the oil jack lift the car,and the surface area of it is 100 times of smaller one. To lift the car mass 1200 kg, how many newtons is the force required to push at a small piston
Strategy
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Pascal's law - pressure applied anywhere to a body of fluid causes a force to be transmitted equally in all directions; the force acts at right angles to any surface in contact with the fluid; "the hydraulic press is an application of Pascal's law" Solution According to Pascal's law; We give the surface area of the big piston is "A", and the small piston is "a". Big piston and small piston will occupy same level of the fluid. Formulae is ; |
Ans. The force required to push at a small piston is 117.6 N
Oil Jack |
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